Distance from Altus to Savigny-le-Temple
The shortest distance (air line) between Altus and Savigny-le-Temple is 4,952.53 mi (7,970.32 km).
How far is Altus from Savigny-le-Temple
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 08:34 (13.01.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 15:34 (13.01.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 4,952.53 miles which is equal to 7,970.32 km.
Altus, Oklahoma, United States
Related Distances from Altus
Savigny-le-Temple, Seine-et-Marne, France