Distance from Altus to Scherpenzeel
The shortest distance (air line) between Altus and Scherpenzeel is 4,930.07 mi (7,934.18 km).
How far is Altus from Scherpenzeel
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 02:43 (23.02.2025)
Scherpenzeel is located in Veluwe, Netherlands within 52° 4' 59.88" N 5° 28' 0.12" E (52.0833, 5.4667) coordinates. The local time in Scherpenzeel is 09:43 (23.02.2025)
The calculated flying distance from Scherpenzeel to Scherpenzeel is 4,930.07 miles which is equal to 7,934.18 km.
Altus, Oklahoma, United States
Related Distances from Altus
Scherpenzeel, Veluwe, Netherlands