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      Distance from Altus to Sobral de Monte Agraco

      The shortest distance (air line) between Altus and Sobral de Monte Agraco is 4,776.26 mi (7,686.65 km).

      How far is Altus from Sobral de Monte Agraco

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 18:02 (25.02.2025)

      Sobral de Monte Agraco is located in Oeste, Portugal within 39° 1' 4.8" N -10° 50' 52.8" W (39.0180, -9.1520) coordinates. The local time in Sobral de Monte Agraco is 00:02 (26.02.2025)

      The calculated flying distance from Sobral de Monte Agraco to Sobral de Monte Agraco is 4,776.26 miles which is equal to 7,686.65 km.

      Altus, Oklahoma, United States

      Related Distances from Altus

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      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
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      Altus to Queens (New York)1,450.68 mi (2,334.64 km)
      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
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      Sobral de Monte Agraco, Oeste, Portugal

      Related Distances to Sobral de Monte Agraco