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      Distance from Altus to Soisy-sous-Montmorency

      The shortest distance (air line) between Altus and Soisy-sous-Montmorency is 4,926.84 mi (7,928.98 km).

      How far is Altus from Soisy-sous-Montmorency

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 06:13 (04.06.2025)

      Soisy-sous-Montmorency is located in Val-d’Oise, France within 48° 59' 16.08" N 2° 17' 58.92" E (48.9878, 2.2997) coordinates. The local time in Soisy-sous-Montmorency is 13:13 (04.06.2025)

      The calculated flying distance from Soisy-sous-Montmorency to Soisy-sous-Montmorency is 4,926.84 miles which is equal to 7,928.98 km.

      Altus, Oklahoma, United States

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      Soisy-sous-Montmorency, Val-d’Oise, France

      Related Distances to Soisy-sous-Montmorency