Distance from Altus to Sveti Ivan Zelina
The shortest distance (air line) between Altus and Sveti Ivan Zelina is 5,573.61 mi (8,969.86 km).
How far is Altus from Sveti Ivan Zelina
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 02:53 (10.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 09:53 (10.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,573.61 miles which is equal to 8,969.86 km.
Altus, Oklahoma, United States
Related Distances from Altus
Sveti Ivan Zelina, Zagrebačka županija, Croatia