Distance from Altus to Vetraz-Monthoux
The shortest distance (air line) between Altus and Vetraz-Monthoux is 5,187.61 mi (8,348.65 km).
How far is Altus from Vetraz-Monthoux
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 06:38 (14.01.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 13:38 (14.01.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 5,187.61 miles which is equal to 8,348.65 km.
Altus, Oklahoma, United States
Related Distances from Altus
Vetraz-Monthoux, Haute-Savoie, France