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      Distance from Altus to Villefranche-de-Rouergue

      The shortest distance (air line) between Altus and Villefranche-de-Rouergue is 5,087.20 mi (8,187.06 km).

      How far is Altus from Villefranche-de-Rouergue

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 16:55 (14.01.2025)

      Villefranche-de-Rouergue is located in Aveyron, France within 44° 21' 9" N 2° 2' 3.12" E (44.3525, 2.0342) coordinates. The local time in Villefranche-de-Rouergue is 23:55 (14.01.2025)

      The calculated flying distance from Villefranche-de-Rouergue to Villefranche-de-Rouergue is 5,087.20 miles which is equal to 8,187.06 km.

      Altus, Oklahoma, United States

      Related Distances from Altus

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      Altus to Tampa (Florida)1,094.51 mi (1,761.45 km)
      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
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      Altus to Queens (New York)1,450.68 mi (2,334.64 km)
      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
      Altus to Dallas (Texas)194.57 mi (313.14 km)
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      Villefranche-de-Rouergue, Aveyron, France

      Related Distances to Villefranche-de-Rouergue