Distance from Altus to s-Heerenberg
The shortest distance (air line) between Altus and s-Heerenberg is 4,965.64 mi (7,991.43 km).
How far is Altus from s-Heerenberg
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 02:37 (23.02.2025)
s-Heerenberg is located in Achterhoek, Netherlands within 51° 52' 35.04" N 6° 14' 44.88" E (51.8764, 6.2458) coordinates. The local time in s-Heerenberg is 09:37 (23.02.2025)
The calculated flying distance from s-Heerenberg to s-Heerenberg is 4,965.64 miles which is equal to 7,991.43 km.
Altus, Oklahoma, United States
Related Distances from Altus
s-Heerenberg, Achterhoek, Netherlands