Distance from Amarillo to Saint-Genis-Pouilly
The shortest distance (air line) between Amarillo and Saint-Genis-Pouilly is 5,246.40 mi (8,443.27 km).
How far is Amarillo from Saint-Genis-Pouilly
Amarillo is located in Texas, United States within 35° 11' 54.24" N -102° 10' 6.24" W (35.1984, -101.8316) coordinates. The local time in Amarillo is 23:30 (14.02.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 06:30 (15.02.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 5,246.40 miles which is equal to 8,443.27 km.
Amarillo, Texas, United States
Related Distances from Amarillo
Saint-Genis-Pouilly, Ain, France