Distance from Americus to Janow Lubelski
The shortest distance (air line) between Americus and Janow Lubelski is 5,187.96 mi (8,349.21 km).
How far is Americus from Janow Lubelski
Americus is located in Georgia, United States within 32° 4' 24.96" N -85° 46' 30.72" W (32.0736, -84.2248) coordinates. The local time in Americus is 14:04 (24.02.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 20:04 (24.02.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 5,187.96 miles which is equal to 8,349.21 km.
Americus, Georgia, United States
Related Distances from Americus
Janow Lubelski, Puławski, Poland