Distance from Amherst to Tomaszow Lubelski
The shortest distance (air line) between Amherst and Tomaszow Lubelski is 4,670.49 mi (7,516.43 km).
How far is Amherst from Tomaszow Lubelski
Amherst is located in Ohio, United States within 41° 24' 7.92" N -83° 46' 10.92" W (41.4022, -82.2303) coordinates. The local time in Amherst is 22:01 (27.02.2025)
Tomaszow Lubelski is located in Chełmsko-zamojski, Poland within 50° 27' 0" N 23° 25' 0.12" E (50.4500, 23.4167) coordinates. The local time in Tomaszow Lubelski is 04:01 (28.02.2025)
The calculated flying distance from Tomaszow Lubelski to Tomaszow Lubelski is 4,670.49 miles which is equal to 7,516.43 km.
Related Distances from Amherst
Tomaszow Lubelski, Chełmsko-zamojski, Poland