Distance from Amsterdam to Secaucus
The shortest distance (air line) between Amsterdam and Secaucus is 3,641.95 mi (5,861.15 km).
How far is Amsterdam from Secaucus
Amsterdam is located in Groot-Amsterdam, Netherlands within 52° 22' 22.08" N 4° 53' 36.96" E (52.3728, 4.8936) coordinates. The local time in Amsterdam is 21:03 (06.01.2026)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 15:03 (06.01.2026)
The calculated flying distance from Secaucus to Secaucus is 3,641.95 miles which is equal to 5,861.15 km.
Amsterdam, Groot-Amsterdam, Netherlands
Related Distances from Amsterdam
Secaucus, New Jersey, United States