Distance from Amsterdam to Sevierville
The shortest distance (air line) between Amsterdam and Sevierville is 4,247.50 mi (6,835.69 km).
How far is Amsterdam from Sevierville
Amsterdam is located in Groot-Amsterdam, Netherlands within 52° 22' 22.08" N 4° 53' 36.96" E (52.3728, 4.8936) coordinates. The local time in Amsterdam is 03:52 (03.01.2026)
Sevierville is located in Tennessee, United States within 35° 53' 13.92" N -84° 25' 55.92" W (35.8872, -83.5678) coordinates. The local time in Sevierville is 21:52 (02.01.2026)
The calculated flying distance from Sevierville to Sevierville is 4,247.50 miles which is equal to 6,835.69 km.
Amsterdam, Groot-Amsterdam, Netherlands
Related Distances from Amsterdam
Sevierville, Tennessee, United States