Distance from Anderson to Sint-Kruis
The shortest distance (air line) between Anderson and Sint-Kruis is 4,095.90 mi (6,591.72 km).
How far is Anderson from Sint-Kruis
Anderson is located in Indiana, United States within 40° 5' 20.76" N -86° 18' 38.88" W (40.0891, -85.6892) coordinates. The local time in Anderson is 14:02 (07.04.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 20:02 (07.04.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,095.90 miles which is equal to 6,591.72 km.
Anderson, Indiana, United States
Related Distances from Anderson
Sint-Kruis, Arr. Brugge, Belgium