Distance from Antioch to Reguengos de Monsaraz
The shortest distance (air line) between Antioch and Reguengos de Monsaraz is 5,707.92 mi (9,186.01 km).
How far is Antioch from Reguengos de Monsaraz
Antioch is located in California, United States within 37° 58' 43.32" N -122° 12' 14.4" W (37.9787, -121.7960) coordinates. The local time in Antioch is 13:05 (08.02.2025)
Reguengos de Monsaraz is located in Alentejo Central, Portugal within 38° 25' 0.12" N -8° 28' 0.12" W (38.4167, -7.5333) coordinates. The local time in Reguengos de Monsaraz is 21:05 (08.02.2025)
The calculated flying distance from Reguengos de Monsaraz to Reguengos de Monsaraz is 5,707.92 miles which is equal to 9,186.01 km.
Antioch, California, United States
Related Distances from Antioch
Reguengos de Monsaraz, Alentejo Central, Portugal