Distance from Antioch to San Angelo
The shortest distance (air line) between Antioch and San Angelo is 1,290.10 mi (2,076.21 km).
How far is Antioch from San Angelo
Antioch is located in California, United States within 37° 58' 43.32" N -122° 12' 14.4" W (37.9787, -121.7960) coordinates. The local time in Antioch is 23:24 (10.01.2026)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 01:24 (11.01.2026)
The calculated flying distance from San Angelo to San Angelo is 1,290.10 miles which is equal to 2,076.21 km.
Antioch, California, United States
Related Distances from Antioch
San Angelo, Texas, United States