Distance from Antioch to Steenokkerzeel
The shortest distance (air line) between Antioch and Steenokkerzeel is 5,487.95 mi (8,832.01 km).
How far is Antioch from Steenokkerzeel
Antioch is located in California, United States within 37° 58' 43.32" N -122° 12' 14.4" W (37.9787, -121.7960) coordinates. The local time in Antioch is 06:26 (19.01.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 15:26 (19.01.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 5,487.95 miles which is equal to 8,832.01 km.
Antioch, California, United States
Related Distances from Antioch
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium