Distance from Asenovgrad to Sevierville
The shortest distance (air line) between Asenovgrad and Sevierville is 5,413.08 mi (8,711.51 km).
How far is Asenovgrad from Sevierville
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 14:51 (14.12.2025)
Sevierville is located in Tennessee, United States within 35° 53' 13.92" N -84° 25' 55.92" W (35.8872, -83.5678) coordinates. The local time in Sevierville is 07:51 (14.12.2025)
The calculated flying distance from Sevierville to Sevierville is 5,413.08 miles which is equal to 8,711.51 km.
Related Distances from Asenovgrad
Sevierville, Tennessee, United States