Distance from Asenovgrad to Vernon Hills
The shortest distance (air line) between Asenovgrad and Vernon Hills is 5,273.20 mi (8,486.40 km).
How far is Asenovgrad from Vernon Hills
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 08:29 (18.12.2025)
Vernon Hills is located in Illinois, United States within 42° 14' 2.4" N -88° 2' 21.12" W (42.2340, -87.9608) coordinates. The local time in Vernon Hills is 00:29 (18.12.2025)
The calculated flying distance from Vernon Hills to Vernon Hills is 5,273.20 miles which is equal to 8,486.40 km.
Related Distances from Asenovgrad
Vernon Hills, Illinois, United States