Distance from Asenovgrad to Wilmington Island
The shortest distance (air line) between Asenovgrad and Wilmington Island is 5,490.87 mi (8,836.71 km).
How far is Asenovgrad from Wilmington Island
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 21:46 (03.01.2026)
Wilmington Island is located in Georgia, United States within 32° 0' 11.88" N -81° 1' 29.28" W (32.0033, -80.9752) coordinates. The local time in Wilmington Island is 14:46 (03.01.2026)
The calculated flying distance from Wilmington Island to Wilmington Island is 5,490.87 miles which is equal to 8,836.71 km.
Related Distances from Asenovgrad
Wilmington Island, Georgia, United States