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      Distance from Ashburn to Sint-Katelijne-Waver

      The shortest distance (air line) between Ashburn and Sint-Katelijne-Waver is 3,876.21 mi (6,238.16 km).

      How far is Ashburn from Sint-Katelijne-Waver

      Ashburn is located in Virginia, United States within 39° 1' 39.72" N -78° 31' 42.96" W (39.0277, -77.4714) coordinates. The local time in Ashburn is 16:36 (17.04.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 22:36 (17.04.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,876.21 miles which is equal to 6,238.16 km.

      Ashburn, Virginia, United States

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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver