Distance from Ashby de la Zouch to Cesky Tesin
The shortest distance (air line) between Ashby de la Zouch and Cesky Tesin is 890.60 mi (1,433.29 km).
How far is Ashby de la Zouch from Cesky Tesin
Ashby de la Zouch is located in Leicestershire CC and Rutland, United Kingdom within 52° 44' 45.6" N -2° 31' 26.4" W (52.7460, -1.4760) coordinates. The local time in Ashby de la Zouch is 02:50 (25.11.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 03:50 (25.11.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 890.60 miles which is equal to 1,433.29 km.
Ashby de la Zouch, Leicestershire CC and Rutland, United Kingdom
Related Distances from Ashby de la Zouch
Cesky Tesin, Moravskoslezský kraj, Czechia