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      Distance from Asheboro to Sint-Pieters-Leeuw

      The shortest distance (air line) between Asheboro and Sint-Pieters-Leeuw is 4,120.97 mi (6,632.06 km).

      How far is Asheboro from Sint-Pieters-Leeuw

      Asheboro is located in North Carolina, United States within 35° 42' 56.88" N -80° 11' 14.28" W (35.7158, -79.8127) coordinates. The local time in Asheboro is 06:18 (23.11.2024)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 12:18 (23.11.2024)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,120.97 miles which is equal to 6,632.06 km.

      Asheboro, North Carolina, United States

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw