Distance from Asheville to Bad Liebenwerda
The shortest distance (air line) between Asheville and Bad Liebenwerda is 4,576.97 mi (7,365.93 km).
How far is Asheville from Bad Liebenwerda
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 01:50 (04.12.2024)
Bad Liebenwerda is located in Elbe-Elster, Germany within 51° 31' 0.12" N 13° 24' 0" E (51.5167, 13.4000) coordinates. The local time in Bad Liebenwerda is 07:50 (04.12.2024)
The calculated flying distance from Bad Liebenwerda to Bad Liebenwerda is 4,576.97 miles which is equal to 7,365.93 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Bad Liebenwerda, Elbe-Elster, Germany