Distance from Asheville to Bad Sassendorf
The shortest distance (air line) between Asheville and Bad Sassendorf is 4,373.16 mi (7,037.93 km).
How far is Asheville from Bad Sassendorf
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 14:59 (11.12.2024)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 20:59 (11.12.2024)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,373.16 miles which is equal to 7,037.93 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Bad Sassendorf, Soest, Germany