Distance from Asheville to Bad Sooden-Allendorf
The shortest distance (air line) between Asheville and Bad Sooden-Allendorf is 4,452.81 mi (7,166.11 km).
How far is Asheville from Bad Sooden-Allendorf
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 02:58 (04.12.2024)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 08:58 (04.12.2024)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,452.81 miles which is equal to 7,166.11 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany