Distance from Asheville to Dimitrovgrad
The shortest distance (air line) between Asheville and Dimitrovgrad is 5,260.78 mi (8,466.41 km).
How far is Asheville from Dimitrovgrad
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 05:53 (23.11.2024)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 11:53 (23.11.2024)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,260.78 miles which is equal to 8,466.41 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Dimitrovgrad, Pirotska oblast, Serbia