Distance from Asheville to Novy Jicin
The shortest distance (air line) between Asheville and Novy Jicin is 4,818.51 mi (7,754.64 km).
How far is Asheville from Novy Jicin
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 19:37 (19.02.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 01:37 (20.02.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 4,818.51 miles which is equal to 7,754.64 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Novy Jicin, Moravskoslezský kraj, Czechia