Distance from Asheville to Sint-Pieters-Leeuw
The shortest distance (air line) between Asheville and Sint-Pieters-Leeuw is 4,239.32 mi (6,822.53 km).
How far is Asheville from Sint-Pieters-Leeuw
Asheville is located in North Carolina, United States within 35° 34' 14.52" N -83° 26' 46.68" W (35.5707, -82.5537) coordinates. The local time in Asheville is 20:29 (26.11.2024)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 02:29 (27.11.2024)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,239.32 miles which is equal to 6,822.53 km.
Asheville, North Carolina, United States
Related Distances from Asheville
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium