Distance from Ashington to Sint-Pieters-Leeuw
The shortest distance (air line) between Ashington and Sint-Pieters-Leeuw is 388.18 mi (624.72 km).
How far is Ashington from Sint-Pieters-Leeuw
Ashington is located in Northumberland, United Kingdom within 55° 10' 51.6" N -2° 25' 55.2" W (55.1810, -1.5680) coordinates. The local time in Ashington is 17:37 (24.11.2024)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 18:37 (24.11.2024)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 388.18 miles which is equal to 624.72 km.
Ashington, Northumberland, United Kingdom
Related Distances from Ashington
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium