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      Distance from Auburn Hills to Skanderborg

      The shortest distance (air line) between Auburn Hills and Skanderborg is 3,962.51 mi (6,377.04 km).

      How far is Auburn Hills from Skanderborg

      Auburn Hills is located in Michigan, United States within 42° 40' 24.6" N -84° 45' 18.72" W (42.6735, -83.2448) coordinates. The local time in Auburn Hills is 18:44 (02.12.2024)

      Skanderborg is located in Østjylland, Denmark within 56° 2' 30.12" N 9° 55' 30" E (56.0417, 9.9250) coordinates. The local time in Skanderborg is 00:44 (03.12.2024)

      The calculated flying distance from Skanderborg to Skanderborg is 3,962.51 miles which is equal to 6,377.04 km.

      Auburn Hills, Michigan, United States

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      Skanderborg, Østjylland, Denmark

      Related Distances to Skanderborg

      CitiesDistance
      Horsens to Skanderborg13.00 mi (20.92 km)
      Aarhus to Skanderborg13.60 mi (21.88 km)
      Silkeborg to Skanderborg17.39 mi (27.99 km)
      Vejle to Skanderborg27.11 mi (43.62 km)
      Randers to Skanderborg29.03 mi (46.71 km)
      Fredericia to Skanderborg33.52 mi (53.94 km)
      Viborg to Skanderborg33.74 mi (54.30 km)
      Herning to Skanderborg36.85 mi (59.30 km)
      Kolding to Skanderborg41.44 mi (66.69 km)
      Odense to Skanderborg48.14 mi (77.47 km)
      Holstebro to Skanderborg54.86 mi (88.28 km)
      Esbjerg to Skanderborg69.11 mi (111.22 km)
      Aalborg to Skanderborg69.67 mi (112.12 km)
      Norresundby to Skanderborg70.82 mi (113.98 km)
      Slagelse to Skanderborg70.88 mi (114.07 km)
      Holbaek to Skanderborg73.22 mi (117.83 km)
      Soro to Skanderborg76.45 mi (123.03 km)
      Roskilde to Skanderborg87.98 mi (141.59 km)
      Naestved to Skanderborg91.08 mi (146.58 km)
      Hillerod to Skanderborg92.73 mi (149.24 km)
      Taastrup to Skanderborg96.01 mi (154.52 km)
      Koge to Skanderborg96.56 mi (155.40 km)
      Horsholm to Skanderborg100.52 mi (161.77 km)
      Helsingor to Skanderborg103.56 mi (166.67 km)
      Copenhagen to Skanderborg105.56 mi (169.88 km)