Distance from Auburndale to Sint-Andries
The shortest distance (air line) between Auburndale and Sint-Andries is 4,522.72 mi (7,278.61 km).
How far is Auburndale from Sint-Andries
Auburndale is located in Florida, United States within 28° 5' 46.68" N -82° 11' 55.68" W (28.0963, -81.8012) coordinates. The local time in Auburndale is 09:01 (18.03.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 15:01 (18.03.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,522.72 miles which is equal to 7,278.61 km.
Auburndale, Florida, United States
Related Distances from Auburndale
Sint-Andries, Arr. Brugge, Belgium