Distance from Austintown to Bad Sassendorf
The shortest distance (air line) between Austintown and Bad Sassendorf is 4,035.35 mi (6,494.27 km).
How far is Austintown from Bad Sassendorf
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 04:59 (02.12.2024)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 10:59 (02.12.2024)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,035.35 miles which is equal to 6,494.27 km.
Austintown, Ohio, United States
Related Distances from Austintown
Bad Sassendorf, Soest, Germany