Distance from Austintown to Bad Sooden-Allendorf
The shortest distance (air line) between Austintown and Bad Sooden-Allendorf is 4,114.02 mi (6,620.88 km).
How far is Austintown from Bad Sooden-Allendorf
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 04:49 (02.12.2024)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 10:49 (02.12.2024)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,114.02 miles which is equal to 6,620.88 km.
Austintown, Ohio, United States
Related Distances from Austintown
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany