Distance from Austintown to Boortmeerbeek
The shortest distance (air line) between Austintown and Boortmeerbeek is 3,915.32 mi (6,301.09 km).
How far is Austintown from Boortmeerbeek
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 12:08 (22.11.2024)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 18:08 (22.11.2024)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 3,915.32 miles which is equal to 6,301.09 km.
Austintown, Ohio, United States
Related Distances from Austintown
Boortmeerbeek, Arr. Leuven, Belgium