Distance from Austintown to Heist-op-den-Berg
The shortest distance (air line) between Austintown and Heist-op-den-Berg is 3,918.15 mi (6,305.65 km).
How far is Austintown from Heist-op-den-Berg
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 22:09 (22.11.2024)
Heist-op-den-Berg is located in Arr. Mechelen, Belgium within 51° 4' 59.88" N 4° 43' 0.12" E (51.0833, 4.7167) coordinates. The local time in Heist-op-den-Berg is 04:09 (23.11.2024)
The calculated flying distance from Heist-op-den-Berg to Heist-op-den-Berg is 3,918.15 miles which is equal to 6,305.65 km.
Austintown, Ohio, United States
Related Distances from Austintown
Heist-op-den-Berg, Arr. Mechelen, Belgium