Distance from Austintown to Jablonec nad Nisou
The shortest distance (air line) between Austintown and Jablonec nad Nisou is 4,327.48 mi (6,964.40 km).
How far is Austintown from Jablonec nad Nisou
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 15:16 (27.11.2024)
Jablonec nad Nisou is located in Liberecký kraj, Czechia within 50° 43' 27.84" N 15° 10' 5.16" E (50.7244, 15.1681) coordinates. The local time in Jablonec nad Nisou is 21:16 (27.11.2024)
The calculated flying distance from Jablonec nad Nisou to Jablonec nad Nisou is 4,327.48 miles which is equal to 6,964.40 km.
Austintown, Ohio, United States
Related Distances from Austintown
Jablonec nad Nisou, Liberecký kraj, Czechia