Distance from Austintown to Kampenhout
The shortest distance (air line) between Austintown and Kampenhout is 3,915.92 mi (6,302.06 km).
How far is Austintown from Kampenhout
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 22:59 (22.11.2024)
Kampenhout is located in Arr. Halle-Vilvoorde, Belgium within 50° 56' 28.68" N 4° 32' 58.56" E (50.9413, 4.5496) coordinates. The local time in Kampenhout is 04:59 (23.11.2024)
The calculated flying distance from Kampenhout to Kampenhout is 3,915.92 miles which is equal to 6,302.06 km.
Austintown, Ohio, United States
Related Distances from Austintown
Kampenhout, Arr. Halle-Vilvoorde, Belgium