Distance from Austintown to Levallois-Perret
The shortest distance (air line) between Austintown and Levallois-Perret is 3,887.24 mi (6,255.91 km).
How far is Austintown from Levallois-Perret
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 11:44 (25.11.2024)
Levallois-Perret is located in Hauts-de-Seine, France within 48° 53' 42" N 2° 17' 13.92" E (48.8950, 2.2872) coordinates. The local time in Levallois-Perret is 17:44 (25.11.2024)
The calculated flying distance from Levallois-Perret to Levallois-Perret is 3,887.24 miles which is equal to 6,255.91 km.
Austintown, Ohio, United States
Related Distances from Austintown
Levallois-Perret, Hauts-de-Seine, France