Distance from Austintown to Sint-Joost-ten-Node
The shortest distance (air line) between Austintown and Sint-Joost-ten-Node is 3,912.16 mi (6,296.02 km).
How far is Austintown from Sint-Joost-ten-Node
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 07:04 (23.11.2024)
Sint-Joost-ten-Node is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 0" N 4° 22' 59.88" E (50.8500, 4.3833) coordinates. The local time in Sint-Joost-ten-Node is 13:04 (23.11.2024)
The calculated flying distance from Sint-Joost-ten-Node to Sint-Joost-ten-Node is 3,912.16 miles which is equal to 6,296.02 km.
Austintown, Ohio, United States
Related Distances from Austintown
Sint-Joost-ten-Node, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium