Distance from Austintown to Steenokkerzeel
The shortest distance (air line) between Austintown and Steenokkerzeel is 3,914.98 mi (6,300.55 km).
How far is Austintown from Steenokkerzeel
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 22:44 (26.11.2024)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 04:44 (27.11.2024)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,914.98 miles which is equal to 6,300.55 km.
Austintown, Ohio, United States
Related Distances from Austintown
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium