Distance from Bad Laasphe to Aleksandrow Kujawski
The shortest distance (air line) between Bad Laasphe and Aleksandrow Kujawski is 457.81 mi (736.78 km).
How far is Bad Laasphe from Aleksandrow Kujawski
Bad Laasphe is located in Siegen-Wittgenstein, Germany within 50° 55' 49.08" N 8° 25' 0.12" E (50.9303, 8.4167) coordinates. The local time in Bad Laasphe is 18:30 (24.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 18:30 (24.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 457.81 miles which is equal to 736.78 km.
Bad Laasphe, Siegen-Wittgenstein, Germany
Related Distances from Bad Laasphe
Aleksandrow Kujawski, Włocławski, Poland