Distance from Bad Sooden-Allendorf to Austintown
The shortest distance (air line) between Bad Sooden-Allendorf and Austintown is 4,114.02 mi (6,620.88 km).
How far is Bad Sooden-Allendorf from Austintown
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 03:06 (12.12.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 21:06 (11.12.2025)
The calculated flying distance from Austintown to Austintown is 4,114.02 miles which is equal to 6,620.88 km.
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany
Related Distances from Bad Sooden-Allendorf
Austintown, Ohio, United States