Distance from Bad Sooden-Allendorf to Chesapeake
The shortest distance (air line) between Bad Sooden-Allendorf and Chesapeake is 4,152.22 mi (6,682.35 km).
How far is Bad Sooden-Allendorf from Chesapeake
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 17:55 (12.12.2025)
Chesapeake is located in Virginia, United States within 36° 40' 40.08" N -77° 41' 51.72" W (36.6778, -76.3023) coordinates. The local time in Chesapeake is 11:55 (12.12.2025)
The calculated flying distance from Chesapeake to Chesapeake is 4,152.22 miles which is equal to 6,682.35 km.
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany
Related Distances from Bad Sooden-Allendorf
Chesapeake, Virginia, United States