Distance from Bad Sooden-Allendorf to Dix Hills
The shortest distance (air line) between Bad Sooden-Allendorf and Dix Hills is 3,841.76 mi (6,182.71 km).
How far is Bad Sooden-Allendorf from Dix Hills
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 09:26 (16.12.2025)
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 03:26 (16.12.2025)
The calculated flying distance from Dix Hills to Dix Hills is 3,841.76 miles which is equal to 6,182.71 km.
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany
Related Distances from Bad Sooden-Allendorf
Dix Hills, New York, United States