Distance from Bad Sooden-Allendorf to Fayetteville
The shortest distance (air line) between Bad Sooden-Allendorf and Fayetteville is 4,862.62 mi (7,825.63 km).
How far is Bad Sooden-Allendorf from Fayetteville
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 12:52 (07.01.2026)
Fayetteville is located in Arkansas, United States within 36° 4' 17.04" N -95° 50' 2.04" W (36.0714, -94.1661) coordinates. The local time in Fayetteville is 05:52 (07.01.2026)
The calculated flying distance from Fayetteville to Fayetteville is 4,862.62 miles which is equal to 7,825.63 km.
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany
Related Distances from Bad Sooden-Allendorf
Fayetteville, Arkansas, United States