Distance from Baldwin to Bad Sassendorf
The shortest distance (air line) between Baldwin and Bad Sassendorf is 3,779.35 mi (6,082.27 km).
How far is Baldwin from Bad Sassendorf
Baldwin is located in New York, United States within 40° 39' 3.96" N -74° 23' 33" W (40.6511, -73.6075) coordinates. The local time in Baldwin is 16:57 (01.05.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 22:57 (01.05.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 3,779.35 miles which is equal to 6,082.27 km.
Baldwin, New York, United States
Related Distances from Baldwin
Bad Sassendorf, Soest, Germany