Distance from Baldwin to Diepenbeek
The shortest distance (air line) between Baldwin and Diepenbeek is 3,687.29 mi (5,934.13 km).
How far is Baldwin from Diepenbeek
Baldwin is located in New York, United States within 40° 39' 3.96" N -74° 23' 33" W (40.6511, -73.6075) coordinates. The local time in Baldwin is 01:50 (01.12.2024)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 07:50 (01.12.2024)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,687.29 miles which is equal to 5,934.13 km.
Baldwin, New York, United States
Related Distances from Baldwin
Diepenbeek, Arr. Hasselt, Belgium