Distance from Bayou Cane to Waldshut-Tiengen
The shortest distance (air line) between Bayou Cane and Waldshut-Tiengen is 5,120.24 mi (8,240.24 km).
How far is Bayou Cane from Waldshut-Tiengen
Bayou Cane is located in Louisiana, United States within 29° 37' 27.48" N -91° 14' 56.4" W (29.6243, -90.7510) coordinates. The local time in Bayou Cane is 09:10 (17.12.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 16:10 (17.12.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 5,120.24 miles which is equal to 8,240.24 km.
Bayou Cane, Louisiana, United States
Related Distances from Bayou Cane
Waldshut-Tiengen, Waldshut, Germany