Distance from Bettendorf to Savage
The shortest distance (air line) between Bettendorf and Savage is 263.98 mi (424.84 km).
How far is Bettendorf from Savage
Bettendorf is located in Iowa, United States within 41° 33' 56.52" N -91° 31' 24.6" W (41.5657, -90.4765) coordinates. The local time in Bettendorf is 12:54 (07.01.2026)
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 12:54 (07.01.2026)
The calculated flying distance from Savage to Savage is 263.98 miles which is equal to 424.84 km.
Bettendorf, Iowa, United States
Related Distances from Bettendorf
Savage, Minnesota, United States